可靠性与失效率

串联系统:

Snap1

可靠性=R1*R2*R3…Rn

失效率=λ1 + λ2 + λ3…λn

并联系统:

Snap5

可靠性=1 – ((1-R1)*(1-R2)*(1-R3)…(1-Rn))

失效率= 1/((1/(1*λ1)) + (1/(2*λ2)) + (1/(3*λ3))…(1/(n*λn)))


Total views.

© 2013 - 2024. All rights reserved.

Powered by Hydejack v6.6.1